设A = 2 7，B = 5，则A-B 3 = 128-125 = 3，2^(2^5)1=2^32 1=(2a)^4 1 =16a^4 1 =(1 3×5)a^4 1 =(1(a-b^3)b)a^4 1 =(1 ab-b^4)a^4 1 =(1 ab)a^4-a^4×b^4 1 =(1 ab)a^4-(a^2×b^2 1)(a^2×b^2-1)=(1 ab)a4-(a2×B2 1)(ab 1)=(ab 1)(a4-(a2×B2 1)(a b-1))= 641×6700417
