1.平方和公式n(n+1)(2n+1)/6
2,即1 2+2 2+3 2+…+n 2 = n (n+1) (2n+1)/6(注:n 2 = n的平方)
3.证明1+4+9+…+n 2 = n (n+1) (2n+1)/6